13x+(4x+20)=7x-(-x-29)

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Solution for 13x+(4x+20)=7x-(-x-29) equation: 



13x+(4x+20)=7x-(-x-29)

We move all terms to the left:

13x+(4x+20)-(7x-(-x-29))=0

We add all the numbers together, and all the variables

13x+(4x+20)-(7x-(-1x-29))=0

We get rid of parentheses

13x+4x-(7x-(-1x-29))+20=0



We calculate terms in parentheses: -(7x-(-1x-29)), so:

7x-(-1x-29)

We get rid of parentheses

7x+1x+29

We add all the numbers together, and all the variables

8x+29

Back to the equation:

-(8x+29)



We add all the numbers together, and all the variables

17x-(8x+29)+20=0

We get rid of parentheses

17x-8x-29+20=0

We add all the numbers together, and all the variables

9x-9=0

We move all terms containing x to the left, all other terms to the right

9x=9

x=9/9

x=1

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