13x+14+2(x-4)=6(x-7)+3

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Solution for 13x+14+2(x-4)=6(x-7)+3 equation: 



13x+14+2(x-4)=6(x-7)+3

We move all terms to the left:

13x+14+2(x-4)-(6(x-7)+3)=0

We multiply parentheses

13x+2x-(6(x-7)+3)-8+14=0



We calculate terms in parentheses: -(6(x-7)+3), so:

6(x-7)+3

We multiply parentheses

6x-42+3

We add all the numbers together, and all the variables

6x-39

Back to the equation:

-(6x-39)



We add all the numbers together, and all the variables

15x-(6x-39)+6=0

We get rid of parentheses

15x-6x+39+6=0

We add all the numbers together, and all the variables

9x+45=0

We move all terms containing x to the left, all other terms to the right

9x=-45

x=-45/9

x=-5

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