13x+2-(x-3)=-5-3(x+12)+4x

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Solution for 13x+2-(x-3)=-5-3(x+12)+4x equation: 



13x+2-(x-3)=-5-3(x+12)+4x

We move all terms to the left:

13x+2-(x-3)-(-5-3(x+12)+4x)=0

We get rid of parentheses

13x-x-(-5-3(x+12)+4x)+3+2=0



We calculate terms in parentheses: -(-5-3(x+12)+4x), so:

-5-3(x+12)+4x

determiningTheFunctionDomain
-3(x+12)+4x-5

We add all the numbers together, and all the variables

4x-3(x+12)-5

We multiply parentheses

4x-3x-36-5

We add all the numbers together, and all the variables

x-41

Back to the equation:

-(x-41)



We add all the numbers together, and all the variables

12x-(x-41)+5=0

We get rid of parentheses

12x-x+41+5=0

We add all the numbers together, and all the variables

11x+46=0

We move all terms containing x to the left, all other terms to the right

11x=-46

x=-46/11

x=-4+2/11

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