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13x+3(3x+1)=x+2(10x-7)
We move all terms to the left:
13x+3(3x+1)-(x+2(10x-7))=0
We multiply parentheses
13x+9x-(x+2(10x-7))+3=0
We calculate terms in parentheses: -(x+2(10x-7)), so:We add all the numbers together, and all the variables
x+2(10x-7)
We multiply parentheses
x+20x-14
We add all the numbers together, and all the variables
21x-14
Back to the equation:
-(21x-14)
22x-(21x-14)+3=0
We get rid of parentheses
22x-21x+14+3=0
We add all the numbers together, and all the variables
x+17=0
We move all terms containing x to the left, all other terms to the right
x=-17
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