13x+4(x+1)=17(x+1)-13

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Solution for 13x+4(x+1)=17(x+1)-13 equation:


Simplifying
13x + 4(x + 1) = 17(x + 1) + -13

Reorder the terms:
13x + 4(1 + x) = 17(x + 1) + -13
13x + (1 * 4 + x * 4) = 17(x + 1) + -13
13x + (4 + 4x) = 17(x + 1) + -13

Reorder the terms:
4 + 13x + 4x = 17(x + 1) + -13

Combine like terms: 13x + 4x = 17x
4 + 17x = 17(x + 1) + -13

Reorder the terms:
4 + 17x = 17(1 + x) + -13
4 + 17x = (1 * 17 + x * 17) + -13
4 + 17x = (17 + 17x) + -13

Reorder the terms:
4 + 17x = 17 + -13 + 17x

Combine like terms: 17 + -13 = 4
4 + 17x = 4 + 17x

Add '-4' to each side of the equation.
4 + -4 + 17x = 4 + -4 + 17x

Combine like terms: 4 + -4 = 0
0 + 17x = 4 + -4 + 17x
17x = 4 + -4 + 17x

Combine like terms: 4 + -4 = 0
17x = 0 + 17x
17x = 17x

Add '-17x' to each side of the equation.
17x + -17x = 17x + -17x

Combine like terms: 17x + -17x = 0
0 = 17x + -17x

Combine like terms: 17x + -17x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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