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13x+4x(x+9)=104
We move all terms to the left:
13x+4x(x+9)-(104)=0
We multiply parentheses
4x^2+13x+36x-104=0
We add all the numbers together, and all the variables
4x^2+49x-104=0
a = 4; b = 49; c = -104;
Δ = b2-4ac
Δ = 492-4·4·(-104)
Δ = 4065
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(49)-\sqrt{4065}}{2*4}=\frac{-49-\sqrt{4065}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(49)+\sqrt{4065}}{2*4}=\frac{-49+\sqrt{4065}}{8} $
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