13x+9=-3(2x+3)+3(x-4)+1

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Solution for 13x+9=-3(2x+3)+3(x-4)+1 equation: 



13x+9=-3(2x+3)+3(x-4)+1

We move all terms to the left:

13x+9-(-3(2x+3)+3(x-4)+1)=0



We calculate terms in parentheses: -(-3(2x+3)+3(x-4)+1), so:

-3(2x+3)+3(x-4)+1

We multiply parentheses

-6x+3x-9-12+1

We add all the numbers together, and all the variables

-3x-20

Back to the equation:

-(-3x-20)



We get rid of parentheses

13x+3x+20+9=0

We add all the numbers together, and all the variables

16x+29=0

We move all terms containing x to the left, all other terms to the right

16x=-29

x=-29/16

x=-1+13/16

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