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13x-10=5x-(3x+7)+(-x+3)
We move all terms to the left:
13x-10-(5x-(3x+7)+(-x+3))=0
We add all the numbers together, and all the variables
13x-(5x-(3x+7)+(-1x+3))-10=0
We calculate terms in parentheses: -(5x-(3x+7)+(-1x+3)), so:We get rid of parentheses
5x-(3x+7)+(-1x+3)
We get rid of parentheses
5x-3x-1x-7+3
We add all the numbers together, and all the variables
x-4
Back to the equation:
-(x-4)
13x-x+4-10=0
We add all the numbers together, and all the variables
12x-6=0
We move all terms containing x to the left, all other terms to the right
12x=6
x=6/12
x=1/2
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