13x-2(3x-7)=5(6x+8)-22x-32

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Solution for 13x-2(3x-7)=5(6x+8)-22x-32 equation: 



13x-2(3x-7)=5(6x+8)-22x-32

We move all terms to the left:

13x-2(3x-7)-(5(6x+8)-22x-32)=0

We multiply parentheses

13x-6x-(5(6x+8)-22x-32)+14=0



We calculate terms in parentheses: -(5(6x+8)-22x-32), so:

5(6x+8)-22x-32

We add all the numbers together, and all the variables

-22x+5(6x+8)-32

We multiply parentheses

-22x+30x+40-32

We add all the numbers together, and all the variables

8x+8

Back to the equation:

-(8x+8)



We add all the numbers together, and all the variables

7x-(8x+8)+14=0

We get rid of parentheses

7x-8x-8+14=0

We add all the numbers together, and all the variables

-1x+6=0

We move all terms containing x to the left, all other terms to the right

-x=-6

x=-6/-1

x=+6

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