13x-33=7x(2x-4)

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Solution for 13x-33=7x(2x-4) equation: 



13x-33=7x(2x-4)

We move all terms to the left:

13x-33-(7x(2x-4))=0



We calculate terms in parentheses: -(7x(2x-4)), so:

7x(2x-4)

We multiply parentheses

14x^2-28x

Back to the equation:

-(14x^2-28x)



We get rid of parentheses

-14x^2+13x+28x-33=0

We add all the numbers together, and all the variables

-14x^2+41x-33=0

a = -14; b = 41; c = -33;
Δ = b2-4ac
Δ = 412-4·(-14)·(-33)
Δ = -167
Delta is less than zero, so there is no solution for the equation

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