13x-4(4x-5)=6(3x+4)-7(3x-1)

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Solution for 13x-4(4x-5)=6(3x+4)-7(3x-1) equation: 



13x-4(4x-5)=6(3x+4)-7(3x-1)

We move all terms to the left:

13x-4(4x-5)-(6(3x+4)-7(3x-1))=0

We multiply parentheses

13x-16x-(6(3x+4)-7(3x-1))+20=0



We calculate terms in parentheses: -(6(3x+4)-7(3x-1)), so:

6(3x+4)-7(3x-1)

We multiply parentheses

18x-21x+24+7

We add all the numbers together, and all the variables

-3x+31

Back to the equation:

-(-3x+31)



We add all the numbers together, and all the variables

-3x-(-3x+31)+20=0

We get rid of parentheses

-3x+3x-31+20=0

We add all the numbers together, and all the variables

-11!=0

There is no solution for this equation

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