13x-41=10(x-2)+3x

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Solution for 13x-41=10(x-2)+3x equation: 



13x-41=10(x-2)+3x

We move all terms to the left:

13x-41-(10(x-2)+3x)=0



We calculate terms in parentheses: -(10(x-2)+3x), so:

10(x-2)+3x

We add all the numbers together, and all the variables

3x+10(x-2)

We multiply parentheses

3x+10x-20

We add all the numbers together, and all the variables

13x-20

Back to the equation:

-(13x-20)



We get rid of parentheses

13x-13x+20-41=0

We add all the numbers together, and all the variables

-21!=0

There is no solution for this equation

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