13x-9x+20=3(x+10)

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Solution for 13x-9x+20=3(x+10) equation: 



13x-9x+20=3(x+10)

We move all terms to the left:

13x-9x+20-(3(x+10))=0

We add all the numbers together, and all the variables

4x-(3(x+10))+20=0



We calculate terms in parentheses: -(3(x+10)), so:

3(x+10)

We multiply parentheses

3x+30

Back to the equation:

-(3x+30)



We get rid of parentheses

4x-3x-30+20=0

We add all the numbers together, and all the variables

x-10=0

We move all terms containing x to the left, all other terms to the right

x=10

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