13x/2x2-7=1

Solution for 13x/2x2-7=1 equation:

13x/2x^2-7=1

We move all terms to the left:

13x/2x^2-7-(1)=0


Domain of the equation: 2x^2!=0

x^2!=0/2

x^2!=√0

x!=0

x∈R


We add all the numbers together, and all the variables

13x/2x^2-8=0

We multiply all the terms by the denominator


13x-8*2x^2=0

Wy multiply elements

-16x^2+13x=0

a = -16; b = 13; c = 0;
Δ = b2-4ac
Δ = 132-4·(-16)·0
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{169}=13$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-13}{2*-16}=\frac{-26}{-32}
=13/16
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+13}{2*-16}=\frac{0}{-32}
=0
$