13x2+26x+4=0

Solution for 13x2+26x+4=0 equation:

13x^2+26x+4=0

a = 13; b = 26; c = +4;
Δ = b2-4ac
Δ = 262-4·13·4
Δ = 468
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{468}=\sqrt{36*13}=\sqrt{36}*\sqrt{13}=6\sqrt{13}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(26)-6\sqrt{13}}{2*13}=\frac{-26-6\sqrt{13}}{26}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(26)+6\sqrt{13}}{2*13}=\frac{-26+6\sqrt{13}}{26}
$