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13x^2-11x-2=0
a = 13; b = -11; c = -2;
Δ = b2-4ac
Δ = -112-4·13·(-2)
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{225}=15$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-15}{2*13}=\frac{-4}{26} =-2/13 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+15}{2*13}=\frac{26}{26} =1 $
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