13x2-26x-182=13

Solution for 13x2-26x-182=13 equation:

13x^2-26x-182=13

We move all terms to the left:

13x^2-26x-182-(13)=0

We add all the numbers together, and all the variables

13x^2-26x-195=0

a = 13; b = -26; c = -195;
Δ = b2-4ac
Δ = -262-4·13·(-195)
Δ = 10816
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{10816}=104$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-26)-104}{2*13}=\frac{-78}{26}
=-3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-26)+104}{2*13}=\frac{130}{26}
=5
$