13x2-8x-6=0

Solution for 13x2-8x-6=0 equation:

13x^2-8x-6=0

a = 13; b = -8; c = -6;
Δ = b2-4ac
Δ = -82-4·13·(-6)
Δ = 376
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{376}=\sqrt{4*94}=\sqrt{4}*\sqrt{94}=2\sqrt{94}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-2\sqrt{94}}{2*13}=\frac{8-2\sqrt{94}}{26}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+2\sqrt{94}}{2*13}=\frac{8+2\sqrt{94}}{26}
$