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13x^2-x+5=-2x^2+11
We move all terms to the left:
13x^2-x+5-(-2x^2+11)=0
We add all the numbers together, and all the variables
13x^2-(-2x^2+11)-1x+5=0
We get rid of parentheses
13x^2+2x^2-1x-11+5=0
We add all the numbers together, and all the variables
15x^2-1x-6=0
a = 15; b = -1; c = -6;
Δ = b2-4ac
Δ = -12-4·15·(-6)
Δ = 361
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{361}=19$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-19}{2*15}=\frac{-18}{30} =-3/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+19}{2*15}=\frac{20}{30} =2/3 $
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