13x=(4+x)2-3x-(4-x)2

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Solution for 13x=(4+x)2-3x-(4-x)2 equation: 



13x=(4+x)2-3x-(4-x)2

We move all terms to the left:

13x-((4+x)2-3x-(4-x)2)=0

We add all the numbers together, and all the variables

13x-((x+4)2-3x-(-1x+4)2)=0



We calculate terms in parentheses: -((x+4)2-3x-(-1x+4)2), so:

(x+4)2-3x-(-1x+4)2

We add all the numbers together, and all the variables

-3x+(x+4)2-(-1x+4)2

We multiply parentheses

-3x+2x+2x+8-8

We add all the numbers together, and all the variables

x

Back to the equation:

-(x)



We add all the numbers together, and all the variables

12x=0

x=0/12

x=0

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