13x=(4+x)2-3x-(4-x)2

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Solution for 13x=(4+x)2-3x-(4-x)2 equation:



13x=(4+x)2-3x-(4-x)2
We move all terms to the left:
13x-((4+x)2-3x-(4-x)2)=0
We add all the numbers together, and all the variables
13x-((x+4)2-3x-(-1x+4)2)=0
We calculate terms in parentheses: -((x+4)2-3x-(-1x+4)2), so:
(x+4)2-3x-(-1x+4)2
We add all the numbers together, and all the variables
-3x+(x+4)2-(-1x+4)2
We multiply parentheses
-3x+2x+2x+8-8
We add all the numbers together, and all the variables
x
Back to the equation:
-(x)
We add all the numbers together, and all the variables
12x=0
x=0/12
x=0

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