13x=2-(x-3)=x-5-3(x+12)+4x

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Solution for 13x=2-(x-3)=x-5-3(x+12)+4x equation: 



13x=2-(x-3)=x-5-3(x+12)+4x

We move all terms to the left:

13x-(2-(x-3))=0



We calculate terms in parentheses: -(2-(x-3)), so:

2-(x-3)

determiningTheFunctionDomain
-(x-3)+2

We get rid of parentheses

-x+3+2

We add all the numbers together, and all the variables

-1x+5

Back to the equation:

-(-1x+5)



We get rid of parentheses

13x+1x-5=0

We add all the numbers together, and all the variables

14x-5=0

We move all terms containing x to the left, all other terms to the right

14x=5

x=5/14

x=5/14

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