13x=4(3x-2)+1

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Solution for 13x=4(3x-2)+1 equation:



13x=4(3x-2)+1
We move all terms to the left:
13x-(4(3x-2)+1)=0
We calculate terms in parentheses: -(4(3x-2)+1), so:
4(3x-2)+1
We multiply parentheses
12x-8+1
We add all the numbers together, and all the variables
12x-7
Back to the equation:
-(12x-7)
We get rid of parentheses
13x-12x+7=0
We add all the numbers together, and all the variables
x+7=0
We move all terms containing x to the left, all other terms to the right
x=-7

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