13y+2.5-2/3y=1.2

Solution for 13y+2.5-2/3y=1.2 equation:

13y+2.5-2/3y=1.2

We move all terms to the left:

13y+2.5-2/3y-(1.2)=0


Domain of the equation: 3y!=0

y!=0/3

y!=0

y∈R


We add all the numbers together, and all the variables

13y-2/3y+1.3=0

We multiply all the terms by the denominator


13y*3y+(1.3)*3y-2=0

We multiply parentheses

13y*3y+3.9y-2=0

Wy multiply elements

39y^2+3.9y-2=0

a = 39; b = 3.9; c = -2;
Δ = b2-4ac
Δ = 3.92-4·39·(-2)
Δ = 327.21
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3.9)-\sqrt{327.21}}{2*39}=\frac{-3.9-\sqrt{327.21}}{78}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3.9)+\sqrt{327.21}}{2*39}=\frac{-3.9+\sqrt{327.21}}{78}
$