13y-5=9+3(2y-1)

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Solution for 13y-5=9+3(2y-1) equation: 



13y-5=9+3(2y-1)

We move all terms to the left:

13y-5-(9+3(2y-1))=0



We calculate terms in parentheses: -(9+3(2y-1)), so:

9+3(2y-1)

determiningTheFunctionDomain
3(2y-1)+9

We multiply parentheses

6y-3+9

We add all the numbers together, and all the variables

6y+6

Back to the equation:

-(6y+6)



We get rid of parentheses

13y-6y-6-5=0

We add all the numbers together, and all the variables

7y-11=0

We move all terms containing y to the left, all other terms to the right

7y=11

y=11/7

y=1+4/7

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