13y=-2(y-4)+3y

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Solution for 13y=-2(y-4)+3y equation: 



13y=-2(y-4)+3y

We move all terms to the left:

13y-(-2(y-4)+3y)=0



We calculate terms in parentheses: -(-2(y-4)+3y), so:

-2(y-4)+3y

We add all the numbers together, and all the variables

3y-2(y-4)

We multiply parentheses

3y-2y+8

We add all the numbers together, and all the variables

y+8

Back to the equation:

-(y+8)



We get rid of parentheses

13y-y-8=0

We add all the numbers together, and all the variables

12y-8=0

We move all terms containing y to the left, all other terms to the right

12y=8

y=8/12

y=2/3

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