13z/3-28=6-2z/3

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Solution for 13z/3-28=6-2z/3 equation: 



13z/3-28=6-2z/3

We move all terms to the left:

13z/3-28-(6-2z/3)=0

We add all the numbers together, and all the variables

13z/3-(-2z/3+6)-28=0

We get rid of parentheses

13z/3+2z/3-6-28=0

We multiply all the terms by the denominator


13z+2z-6*3-28*3=0

We add all the numbers together, and all the variables

15z-102=0

We move all terms containing z to the left, all other terms to the right

15z=102

z=102/15

z=6+4/5

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