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14((3y-2)/7)-5y=7
We move all terms to the left:
14((3y-2)/7)-5y-(7)=0
We add all the numbers together, and all the variables
-5y+14((3y-2)/7)-7=0
We multiply all the terms by the denominator
-5y*7)+14((3y-2)-7*7)=0
We add all the numbers together, and all the variables
-5y*7)+14((3y-2)=0
Wy multiply elements
-35y^2=0
a = -35; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-35)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$y=\frac{-b}{2a}=\frac{0}{-70}=0$
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