14(1d+6)=4(1d-3)+10d

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Solution for 14(1d+6)=4(1d-3)+10d equation: 



14(1d+6)=4(1d-3)+10d

We move all terms to the left:

14(1d+6)-(4(1d-3)+10d)=0

We add all the numbers together, and all the variables

14(d+6)-(4(d-3)+10d)=0

We multiply parentheses

14d-(4(d-3)+10d)+84=0



We calculate terms in parentheses: -(4(d-3)+10d), so:

4(d-3)+10d

We add all the numbers together, and all the variables

10d+4(d-3)

We multiply parentheses

10d+4d-12

We add all the numbers together, and all the variables

14d-12

Back to the equation:

-(14d-12)



We get rid of parentheses

14d-14d+12+84=0

We add all the numbers together, and all the variables

96!=0

There is no solution for this equation

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