14(2n-28)=10

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Solution for 14(2n-28)=10 equation: 



14(2n-28)=10

We move all terms to the left:

14(2n-28)-(10)=0

We multiply parentheses

28n-392-10=0

We add all the numbers together, and all the variables

28n-402=0

We move all terms containing n to the left, all other terms to the right

28n=402

n=402/28

n=14+5/14

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