14(3x-12)=21+6

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Solution for 14(3x-12)=21+6 equation: 



14(3x-12)=21+6

We move all terms to the left:

14(3x-12)-(21+6)=0

We add all the numbers together, and all the variables

14(3x-12)-27=0

We multiply parentheses

42x-168-27=0

We add all the numbers together, and all the variables

42x-195=0

We move all terms containing x to the left, all other terms to the right

42x=195

x=195/42

x=4+9/14

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