14(V+2)-2V=3(4v+3)-12

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Solution for 14(V+2)-2V=3(4v+3)-12 equation: 


Simplifying
14(V + 2) + -2V = 3(4v + 3) + -12

Reorder the terms:
14(2 + V) + -2V = 3(4v + 3) + -12
(2 * 14 + V * 14) + -2V = 3(4v + 3) + -12
(28 + 14V) + -2V = 3(4v + 3) + -12

Combine like terms: 14V + -2V = 12V
28 + 12V = 3(4v + 3) + -12

Reorder the terms:
28 + 12V = 3(3 + 4v) + -12
28 + 12V = (3 * 3 + 4v * 3) + -12
28 + 12V = (9 + 12v) + -12

Reorder the terms:
28 + 12V = 9 + -12 + 12v

Combine like terms: 9 + -12 = -3
28 + 12V = -3 + 12v

Solving
28 + 12V = -3 + 12v

Solving for variable 'V'.

Move all terms containing V to the left, all other terms to the right.

Add '-28' to each side of the equation.
28 + -28 + 12V = -3 + -28 + 12v

Combine like terms: 28 + -28 = 0
0 + 12V = -3 + -28 + 12v
12V = -3 + -28 + 12v

Combine like terms: -3 + -28 = -31
12V = -31 + 12v

Divide each side by '12'.
V = -2.583333333 + v

Simplifying
V = -2.583333333 + v

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