14(r+2)=4(2-2r)

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Solution for 14(r+2)=4(2-2r) equation: 



14(r+2)=4(2-2r)

We move all terms to the left:

14(r+2)-(4(2-2r))=0

We add all the numbers together, and all the variables

14(r+2)-(4(-2r+2))=0

We multiply parentheses

14r-(4(-2r+2))+28=0



We calculate terms in parentheses: -(4(-2r+2)), so:

4(-2r+2)

We multiply parentheses

-8r+8

Back to the equation:

-(-8r+8)



We get rid of parentheses

14r+8r-8+28=0

We add all the numbers together, and all the variables

22r+20=0

We move all terms containing r to the left, all other terms to the right

22r=-20

r=-20/22

r=-10/11

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