14(s+8)(s-4)=

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Solution for 14(s+8)(s-4)= equation:



14(s+8)(s-4)=
We move all terms to the left:
14(s+8)(s-4)-()=0
We add all the numbers together, and all the variables
14(s+8)(s-4)=0
We multiply parentheses ..
14(+s^2-4s+8s-32)=0
We multiply parentheses
14s^2-56s+112s-448=0
We add all the numbers together, and all the variables
14s^2+56s-448=0
a = 14; b = 56; c = -448;
Δ = b2-4ac
Δ = 562-4·14·(-448)
Δ = 28224
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{28224}=168$
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(56)-168}{2*14}=\frac{-224}{28} =-8 $
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(56)+168}{2*14}=\frac{112}{28} =4 $

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