14(t-3)+4t=6(3t+4)-12

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Solution for 14(t-3)+4t=6(3t+4)-12 equation: 



14(t-3)+4t=6(3t+4)-12

We move all terms to the left:

14(t-3)+4t-(6(3t+4)-12)=0

We add all the numbers together, and all the variables

4t+14(t-3)-(6(3t+4)-12)=0

We multiply parentheses

4t+14t-(6(3t+4)-12)-42=0



We calculate terms in parentheses: -(6(3t+4)-12), so:

6(3t+4)-12

We multiply parentheses

18t+24-12

We add all the numbers together, and all the variables

18t+12

Back to the equation:

-(18t+12)



We add all the numbers together, and all the variables

18t-(18t+12)-42=0

We get rid of parentheses

18t-18t-12-42=0

We add all the numbers together, and all the variables

-54!=0

There is no solution for this equation

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