14(t-4)+7t=7(3t+4)-11

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Solution for 14(t-4)+7t=7(3t+4)-11 equation: 



14(t-4)+7t=7(3t+4)-11

We move all terms to the left:

14(t-4)+7t-(7(3t+4)-11)=0

We add all the numbers together, and all the variables

7t+14(t-4)-(7(3t+4)-11)=0

We multiply parentheses

7t+14t-(7(3t+4)-11)-56=0



We calculate terms in parentheses: -(7(3t+4)-11), so:

7(3t+4)-11

We multiply parentheses

21t+28-11

We add all the numbers together, and all the variables

21t+17

Back to the equation:

-(21t+17)



We add all the numbers together, and all the variables

21t-(21t+17)-56=0

We get rid of parentheses

21t-21t-17-56=0

We add all the numbers together, and all the variables

-73!=0

There is no solution for this equation

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