14(t-5)+4t=6(3t+2)-11

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Solution for 14(t-5)+4t=6(3t+2)-11 equation: 


Simplifying
14(t + -5) + 4t = 6(3t + 2) + -11

Reorder the terms:
14(-5 + t) + 4t = 6(3t + 2) + -11
(-5 * 14 + t * 14) + 4t = 6(3t + 2) + -11
(-70 + 14t) + 4t = 6(3t + 2) + -11

Combine like terms: 14t + 4t = 18t
-70 + 18t = 6(3t + 2) + -11

Reorder the terms:
-70 + 18t = 6(2 + 3t) + -11
-70 + 18t = (2 * 6 + 3t * 6) + -11
-70 + 18t = (12 + 18t) + -11

Reorder the terms:
-70 + 18t = 12 + -11 + 18t

Combine like terms: 12 + -11 = 1
-70 + 18t = 1 + 18t

Add '-18t' to each side of the equation.
-70 + 18t + -18t = 1 + 18t + -18t

Combine like terms: 18t + -18t = 0
-70 + 0 = 1 + 18t + -18t
-70 = 1 + 18t + -18t

Combine like terms: 18t + -18t = 0
-70 = 1 + 0
-70 = 1

Solving
-70 = 1

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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