14(t-5)+7=7(3t+2)-8

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Solution for 14(t-5)+7=7(3t+2)-8 equation: 



14(t-5)+7=7(3t+2)-8

We move all terms to the left:

14(t-5)+7-(7(3t+2)-8)=0

We multiply parentheses

14t-(7(3t+2)-8)-70+7=0



We calculate terms in parentheses: -(7(3t+2)-8), so:

7(3t+2)-8

We multiply parentheses

21t+14-8

We add all the numbers together, and all the variables

21t+6

Back to the equation:

-(21t+6)



We add all the numbers together, and all the variables

14t-(21t+6)-63=0

We get rid of parentheses

14t-21t-6-63=0

We add all the numbers together, and all the variables

-7t-69=0

We move all terms containing t to the left, all other terms to the right

-7t=69

t=69/-7

t=-9+6/7

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