14(t-5)+7t=7(3t+2)-10

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Solution for 14(t-5)+7t=7(3t+2)-10 equation:


Simplifying
14(t + -5) + 7t = 7(3t + 2) + -10

Reorder the terms:
14(-5 + t) + 7t = 7(3t + 2) + -10
(-5 * 14 + t * 14) + 7t = 7(3t + 2) + -10
(-70 + 14t) + 7t = 7(3t + 2) + -10

Combine like terms: 14t + 7t = 21t
-70 + 21t = 7(3t + 2) + -10

Reorder the terms:
-70 + 21t = 7(2 + 3t) + -10
-70 + 21t = (2 * 7 + 3t * 7) + -10
-70 + 21t = (14 + 21t) + -10

Reorder the terms:
-70 + 21t = 14 + -10 + 21t

Combine like terms: 14 + -10 = 4
-70 + 21t = 4 + 21t

Add '-21t' to each side of the equation.
-70 + 21t + -21t = 4 + 21t + -21t

Combine like terms: 21t + -21t = 0
-70 + 0 = 4 + 21t + -21t
-70 = 4 + 21t + -21t

Combine like terms: 21t + -21t = 0
-70 = 4 + 0
-70 = 4

Solving
-70 = 4

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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