14(t-5)+7t=7(3t+2)-13

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Solution for 14(t-5)+7t=7(3t+2)-13 equation:


Simplifying
14(t + -5) + 7t = 7(3t + 2) + -13

Reorder the terms:
14(-5 + t) + 7t = 7(3t + 2) + -13
(-5 * 14 + t * 14) + 7t = 7(3t + 2) + -13
(-70 + 14t) + 7t = 7(3t + 2) + -13

Combine like terms: 14t + 7t = 21t
-70 + 21t = 7(3t + 2) + -13

Reorder the terms:
-70 + 21t = 7(2 + 3t) + -13
-70 + 21t = (2 * 7 + 3t * 7) + -13
-70 + 21t = (14 + 21t) + -13

Reorder the terms:
-70 + 21t = 14 + -13 + 21t

Combine like terms: 14 + -13 = 1
-70 + 21t = 1 + 21t

Add '-21t' to each side of the equation.
-70 + 21t + -21t = 1 + 21t + -21t

Combine like terms: 21t + -21t = 0
-70 + 0 = 1 + 21t + -21t
-70 = 1 + 21t + -21t

Combine like terms: 21t + -21t = 0
-70 = 1 + 0
-70 = 1

Solving
-70 = 1

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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