14(v+1)-2v-4=(3v+3)-16

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Solution for 14(v+1)-2v-4=(3v+3)-16 equation: 



14(v+1)-2v-4=(3v+3)-16

We move all terms to the left:

14(v+1)-2v-4-((3v+3)-16)=0

We add all the numbers together, and all the variables

-2v+14(v+1)-((3v+3)-16)-4=0

We multiply parentheses

-2v+14v-((3v+3)-16)+14-4=0



We calculate terms in parentheses: -((3v+3)-16), so:

(3v+3)-16

We get rid of parentheses

3v+3-16

We add all the numbers together, and all the variables

3v-13

Back to the equation:

-(3v-13)



We add all the numbers together, and all the variables

12v-(3v-13)+10=0

We get rid of parentheses

12v-3v+13+10=0

We add all the numbers together, and all the variables

9v+23=0

We move all terms containing v to the left, all other terms to the right

9v=-23

v=-23/9

v=-2+5/9

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