14(v+2)-2c=4(3v+1)-13

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Solution for 14(v+2)-2c=4(3v+1)-13 equation:


Simplifying
14(v + 2) + -2c = 4(3v + 1) + -13

Reorder the terms:
14(2 + v) + -2c = 4(3v + 1) + -13
(2 * 14 + v * 14) + -2c = 4(3v + 1) + -13
(28 + 14v) + -2c = 4(3v + 1) + -13

Reorder the terms:
28 + -2c + 14v = 4(3v + 1) + -13

Reorder the terms:
28 + -2c + 14v = 4(1 + 3v) + -13
28 + -2c + 14v = (1 * 4 + 3v * 4) + -13
28 + -2c + 14v = (4 + 12v) + -13

Reorder the terms:
28 + -2c + 14v = 4 + -13 + 12v

Combine like terms: 4 + -13 = -9
28 + -2c + 14v = -9 + 12v

Solving
28 + -2c + 14v = -9 + 12v

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-28' to each side of the equation.
28 + -2c + -28 + 14v = -9 + -28 + 12v

Reorder the terms:
28 + -28 + -2c + 14v = -9 + -28 + 12v

Combine like terms: 28 + -28 = 0
0 + -2c + 14v = -9 + -28 + 12v
-2c + 14v = -9 + -28 + 12v

Combine like terms: -9 + -28 = -37
-2c + 14v = -37 + 12v

Add '-14v' to each side of the equation.
-2c + 14v + -14v = -37 + 12v + -14v

Combine like terms: 14v + -14v = 0
-2c + 0 = -37 + 12v + -14v
-2c = -37 + 12v + -14v

Combine like terms: 12v + -14v = -2v
-2c = -37 + -2v

Divide each side by '-2'.
c = 18.5 + v

Simplifying
c = 18.5 + v

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