14(v+2)-2v=3(4v+3)-10

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Solution for 14(v+2)-2v=3(4v+3)-10 equation: 


Simplifying
14(v + 2) + -2v = 3(4v + 3) + -10

Reorder the terms:
14(2 + v) + -2v = 3(4v + 3) + -10
(2 * 14 + v * 14) + -2v = 3(4v + 3) + -10
(28 + 14v) + -2v = 3(4v + 3) + -10

Combine like terms: 14v + -2v = 12v
28 + 12v = 3(4v + 3) + -10

Reorder the terms:
28 + 12v = 3(3 + 4v) + -10
28 + 12v = (3 * 3 + 4v * 3) + -10
28 + 12v = (9 + 12v) + -10

Reorder the terms:
28 + 12v = 9 + -10 + 12v

Combine like terms: 9 + -10 = -1
28 + 12v = -1 + 12v

Add '-12v' to each side of the equation.
28 + 12v + -12v = -1 + 12v + -12v

Combine like terms: 12v + -12v = 0
28 + 0 = -1 + 12v + -12v
28 = -1 + 12v + -12v

Combine like terms: 12v + -12v = 0
28 = -1 + 0
28 = -1

Solving
28 = -1

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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