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14(v+3)-2v=3(4v+1)-6
We move all terms to the left:
14(v+3)-2v-(3(4v+1)-6)=0
We add all the numbers together, and all the variables
-2v+14(v+3)-(3(4v+1)-6)=0
We multiply parentheses
-2v+14v-(3(4v+1)-6)+42=0
We calculate terms in parentheses: -(3(4v+1)-6), so:We add all the numbers together, and all the variables
3(4v+1)-6
We multiply parentheses
12v+3-6
We add all the numbers together, and all the variables
12v-3
Back to the equation:
-(12v-3)
12v-(12v-3)+42=0
We get rid of parentheses
12v-12v+3+42=0
We add all the numbers together, and all the variables
45!=0
There is no solution for this equation
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