14(x+12)=3(x-2)+6

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Solution for 14(x+12)=3(x-2)+6 equation: 



14(x+12)=3(x-2)+6

We move all terms to the left:

14(x+12)-(3(x-2)+6)=0

We multiply parentheses

14x-(3(x-2)+6)+168=0



We calculate terms in parentheses: -(3(x-2)+6), so:

3(x-2)+6

We multiply parentheses

3x-6+6

We add all the numbers together, and all the variables

3x

Back to the equation:

-(3x)



We add all the numbers together, and all the variables

11x+168=0

We move all terms containing x to the left, all other terms to the right

11x=-168

x=-168/11

x=-15+3/11

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