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14(x-4)+3(x+5)=6(7-2x)+14
We move all terms to the left:
14(x-4)+3(x+5)-(6(7-2x)+14)=0
We add all the numbers together, and all the variables
14(x-4)+3(x+5)-(6(-2x+7)+14)=0
We multiply parentheses
14x+3x-(6(-2x+7)+14)-56+15=0
We calculate terms in parentheses: -(6(-2x+7)+14), so:We add all the numbers together, and all the variables
6(-2x+7)+14
We multiply parentheses
-12x+42+14
We add all the numbers together, and all the variables
-12x+56
Back to the equation:
-(-12x+56)
17x-(-12x+56)-41=0
We get rid of parentheses
17x+12x-56-41=0
We add all the numbers together, and all the variables
29x-97=0
We move all terms containing x to the left, all other terms to the right
29x=97
x=97/29
x=3+10/29
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