14(x-4)+3(x+5)=6(7-2x)+14

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Solution for 14(x-4)+3(x+5)=6(7-2x)+14 equation: 



14(x-4)+3(x+5)=6(7-2x)+14

We move all terms to the left:

14(x-4)+3(x+5)-(6(7-2x)+14)=0

We add all the numbers together, and all the variables

14(x-4)+3(x+5)-(6(-2x+7)+14)=0

We multiply parentheses

14x+3x-(6(-2x+7)+14)-56+15=0



We calculate terms in parentheses: -(6(-2x+7)+14), so:

6(-2x+7)+14

We multiply parentheses

-12x+42+14

We add all the numbers together, and all the variables

-12x+56

Back to the equation:

-(-12x+56)



We add all the numbers together, and all the variables

17x-(-12x+56)-41=0

We get rid of parentheses

17x+12x-56-41=0

We add all the numbers together, and all the variables

29x-97=0

We move all terms containing x to the left, all other terms to the right

29x=97

x=97/29

x=3+10/29

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