14(x-4)+3(x+5)=6(7-2x)+4

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Solution for 14(x-4)+3(x+5)=6(7-2x)+4 equation: 



14(x-4)+3(x+5)=6(7-2x)+4

We move all terms to the left:

14(x-4)+3(x+5)-(6(7-2x)+4)=0

We add all the numbers together, and all the variables

14(x-4)+3(x+5)-(6(-2x+7)+4)=0

We multiply parentheses

14x+3x-(6(-2x+7)+4)-56+15=0



We calculate terms in parentheses: -(6(-2x+7)+4), so:

6(-2x+7)+4

We multiply parentheses

-12x+42+4

We add all the numbers together, and all the variables

-12x+46

Back to the equation:

-(-12x+46)



We add all the numbers together, and all the variables

17x-(-12x+46)-41=0

We get rid of parentheses

17x+12x-46-41=0

We add all the numbers together, and all the variables

29x-87=0

We move all terms containing x to the left, all other terms to the right

29x=87

x=87/29

x=3

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