14(x-4)-3(x-9)+(x+4)=0

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Solution for 14(x-4)-3(x-9)+(x+4)=0 equation: 



14(x-4)-3(x-9)+(x+4)=0

We multiply parentheses

14x-3x+(x+4)-56+27=0

We get rid of parentheses

14x-3x+x+4-56+27=0

We add all the numbers together, and all the variables

12x-25=0

We move all terms containing x to the left, all other terms to the right

12x=25

x=25/12

x=2+1/12

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