14(y+2)=3(y-10)+3

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Solution for 14(y+2)=3(y-10)+3 equation: 



14(y+2)=3(y-10)+3

We move all terms to the left:

14(y+2)-(3(y-10)+3)=0

We multiply parentheses

14y-(3(y-10)+3)+28=0



We calculate terms in parentheses: -(3(y-10)+3), so:

3(y-10)+3

We multiply parentheses

3y-30+3

We add all the numbers together, and all the variables

3y-27

Back to the equation:

-(3y-27)



We get rid of parentheses

14y-3y+27+28=0

We add all the numbers together, and all the variables

11y+55=0

We move all terms containing y to the left, all other terms to the right

11y=-55

y=-55/11

y=-5

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