14(y-3)=10(5-y)

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Solution for 14(y-3)=10(5-y) equation: 



14(y-3)=10(5-y)

We move all terms to the left:

14(y-3)-(10(5-y))=0

We add all the numbers together, and all the variables

14(y-3)-(10(-1y+5))=0

We multiply parentheses

14y-(10(-1y+5))-42=0



We calculate terms in parentheses: -(10(-1y+5)), so:

10(-1y+5)

We multiply parentheses

-10y+50

Back to the equation:

-(-10y+50)



We get rid of parentheses

14y+10y-50-42=0

We add all the numbers together, and all the variables

24y-92=0

We move all terms containing y to the left, all other terms to the right

24y=92

y=92/24

y=3+5/6

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