14(y-4)+20y=6y-7

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Solution for 14(y-4)+20y=6y-7 equation: 



14(y-4)+20y=6y-7

We move all terms to the left:

14(y-4)+20y-(6y-7)=0

We add all the numbers together, and all the variables

20y+14(y-4)-(6y-7)=0

We multiply parentheses

20y+14y-(6y-7)-56=0

We get rid of parentheses

20y+14y-6y+7-56=0

We add all the numbers together, and all the variables

28y-49=0

We move all terms containing y to the left, all other terms to the right

28y=49

y=49/28

y=1+3/4

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